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Florida, USA
Joined August 2015
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Pattern to this question is amazing, only genius can spot it? Find the value of the last line.
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3! 3x2x1=6 Yes, the factorial (\(3!\)) must be calculated first. In mathematics, a factorial (\(!\)) is a unary operation (a function applied to a single number). It has a higher precedence than standard binary operators like multiplication, division, addition, and subtraction.
Replying to @tallahoe
Nope you do all of the multiplication first. 5x5 =25 5X3 =15 25+15 answer is 40, I just looked it up on AI 40 is the correct answer.
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If you can solve this in 10 seconds, your math knowledge is above average. Can you find the answer?
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Easy Maths !! What is Your Right Answer ??
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Can you solve it without any hint!!!
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Answer is NOT 36! What is your answer?
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36
Solve it 👀🫨 Don’t Use Calculator Use your Brain 🧠 Drop your answer in comments 🫨👀
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-999 -999 by moving bottom left side pencil of 8 & move in front of 9 as a - making 8 a 9. Move bottom pencil of the 5 to top right side of 5 making a 9.
don’t tuch yallo pencil 👇
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Only Genius !! Can You Solve This ??
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Solve it 👀🫨 Don’t Use Calculator Use your Brain 🧠 Drop your answer in comments 🫨👀
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Easy Maths !! What Is Your Answer??
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Don’t Be In Hurry !! Count Them !! How Many Circles Do You See ??
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Above my pay grade. D 299 answer Part 3: 3Factor out \(2^{99}\) (think of \(2^{99}\) as a single variable \(x\), so \(2x - 1x = 1x\)):
\(2^{99}\cdot (2-1)\)
Only Genius !! Can You Solve This ??
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Part 3 3Factor out \(2^{99}\) (think of \(2^{99}\) as a single variable \(x\), so \(2x - 1x = 1x\)):
\(2^{99}\cdot (2-1)\) D 299 answer
Part 2: 1Rewrite \(2^{100}\) using exponent rules (\(a^{m+n} = a^m \cdot a^n\)):
\(2^{100}=2^{99+1}=2^{99}\cdot 2^{1}\) 2Substitute this back into the original expression:
\(2\cdot 2^{99}-2^{99}\)
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Part 2: 1Rewrite \(2^{100}\) using exponent rules (\(a^{m+n} = a^m \cdot a^n\)):
\(2^{100}=2^{99+1}=2^{99}\cdot 2^{1}\) 2Substitute this back into the original expression:
\(2\cdot 2^{99}-2^{99}\)
Above my pay grade The correct answer is D (\(2^{99}\)). Step-by-Step Solution To solve \(2^{100} - 2^{99}\), we can use the rules of exponents to factor out the common term:
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Above my pay grade The correct answer is D (\(2^{99}\)). Step-by-Step Solution To solve \(2^{100} - 2^{99}\), we can use the rules of exponents to factor out the common term:
Only Genius !! Can You Solve This ??
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