Lorian Saceanu's Inequality for All Triangles cut-the-knot.org/triangle/Lo… #FigureThat #math #geometry #inequality
Alexander Bogomolny retweeted
Here's a couple of solutions cut-the-knot.org/m/Probabili… xitter.cf/CutTheKnotMath/status/…
Seeking problems with 4/7 probability being involved. E.g., Diminishing Hopes II #FigureThat #math #probability cut-the-knot.org/Probability…
Every one can take part in this statistical research. Every one is invited xitter.cf/DegenRolf/status/10141…
You won't believe what great sh*t a psychologist managed to plant on a predatory journal. crimsonpublishers.com/pprs/p…
h/t @maltoesermalte
An Inequality from a Mongolian Exam cut-the-knot.org/m/Algebra/I… #FigureThat #math #algebra #inequality
Let {x_k} be uniformly distributed on say, [-1,1] with the mean=0. Is that true that the variance is at least the square of the median? #FigureThat #math #probability
I was always suspicious of the "pseudo" part in pseudorandom xitter.cf/pomeranian99/status/10…
Russians engineer a way to beat slot machines — for which the casinos have no defense. Insanely interesting piece here by @brendankoerner: wired.com/2017/02/russians-e…
Very elegant xitter.cf/jordancurve/status/101…
Replying to @jordancurve
Simple way to determine if a year is a leap year:
If the last two digits of the year are 00, throw them away and keep only the first two digits. Otherwise, keep only the last two digits. The year is a leap year if what you kept is divisible by 4.
Alexander Bogomolny retweeted
Alexander Bogomolny retweeted
Oh! It's #ff! Add to this ... @republicofmath (of course!) @cbrownLmath @henryseg @margaretwerth @EulersNephew @maanow @timchartier @evelynjlamb @Dr_Kreisberg @NaturalMath @mikeandallie @MathWithMatthew @DavidKButlerUoA @alittlestats @nomad_penguin @aperiodical @NoCOMTC xitter.cf/republicofmath/status/…
I've nothing to say about that. Perhaps somebody will xitter.cf/TigerWhite44/status/10…
Alexander Bogomolny retweeted
Replying to @CutTheKnotMath
It can be equivalently rephrased as saying that if a product of 2n integers is (-1)^n (n!)^2, then their sum is zero.
Here's a couple of solutions cut-the-knot.org/m/Algebra/I…
The discriminant of a quadratic polynomial with integer coefficients equals 23. What can be said about the roots of the polynomial. The more you say, the better. #FigureThat #math #algebra



















